Cho hai biểu thức: \(A = \frac{x}{{x – 3}}\,\,\, ;\,\,\,\,B = \frac{{2x}}{{x + 5}} – \frac{{{x^2} – 15x}}{{{x^2} – 25}}\,\,\,\,\left( {x \ne 0;x \ne 3;x \ne \pm 5} \right)\) Tìm \(x\) để \(Q > 1\).
Cho hai biểu thức: \(A = \frac{x}{{x – 3}}\,\,\, ;\,\,\,\,B = \frac{{2x}}{{x + 5}} – \frac{{{x^2} – 15x}}{{{x^2} – 25}}\,\,\,\,\left( {x \ne 0;x \ne 3;x …