Tháng Sáu 18, 2026

Thẻ: Toán lớp 9

Hỏi Đáp

Đưa thừa số ra ngoài dấu căn: \(a)\,\,\,\sqrt {180{x^2}} \\ b)\,\sqrt {3{x^2} – 6xy + 3{y^2}} \) A \(\begin{array}{l} a)\,\,6x\sqrt 5 \\ b)\,\,\,\left\{ \begin{array}{l} \left( {x – y} \right)\sqrt 3 \,\,\,\,khi\,\,\,\,x \ge y\\ \left( {y – x} \right)\sqrt x \,\,\,\,khi\,\,\,x < y \end{array} \right.. \end{array}\) B \(\begin{array}{l} a)\,\,\, – 6x\sqrt 5 \\ b)\,\,\left( {x – y} \right)\sqrt 3 \end{array}\) C \(\begin{array}{l} a)\,\,\left\{ \begin{array}{l} 6x\sqrt 5 \,\,\,khi\,\,\,x \ge 0\\ – 6x\sqrt 5 \,\,\,\,khi\,\,\,x < 0 \end{array} \right.\\ b)\,\,\,\left\{ \begin{array}{l} \left( {x – y} \right)\sqrt 3 \,\,\,khi\,\,\,x \ge 0\\ \left( {y – x} \right)\sqrt 3 \,\,\,khi\,\,\,x < y \end{array} \right.. \end{array}\) D \(\begin{array}{l} a)\,\, – 6x\sqrt 5 \\ b)\,\, – \left( {x – y} \right)\sqrt 3 \end{array}\)

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Đưa thừa số ra ngoài dấu căn: \(a)\,\,\,\sqrt {180{x^2}} \\ b)\,\sqrt {3{x^2} – 6xy + 3{y^2}} \) A \(\begin{array}{l} a)\,\,6x\sqrt 5 \\ b)\,\,\,\left\{ \begin{array}{l} \left( …

Hỏi Đáp

Tính: \(\begin{array}{l}a)\,\,\sqrt {\frac{{289}}{{225}}} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,b)\,\,\sqrt {2\frac{{14}}{{25}}} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,c)\,\,\sqrt {\frac{{0,25}}{9}} \\d)\,\,\sqrt {1\frac{{16}}{9}.5\frac{4}{9}.0,01} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,e)\,\,\sqrt {\frac{{{{149}^2} – {{76}^2}}}{{{{457}^2} – {{384}^2}}}} \end{array}\) A \(\begin{array}{l} a)\,\,\,\frac{{27}}{{15}} & & & b)\,\,\frac{8}{5}\\ c)\,\,\frac{1}{6} & & & d)\,\,\frac{7}{{24}}\\ e)\,\,\frac{{15}}{{29}} \end{array}\) B \(\begin{array}{l} a)\,\,\,\frac{{17}}{{15}} & & & b)\,\,\frac{8}{5}\\ c)\,\,\frac{1}{6} & & & d)\,\,\frac{17}{{24}}\\ e)\,\,\frac{{15}}{{29}} \end{array}\) C \(\begin{array}{l} a)\,\,\,\frac{{17}}{{15}} & & & b)\,\,\frac{8}{5}\\ c)\,\,\frac{1}{6} & & & d)\,\,\frac{7}{{24}}\\ e)\,\,\frac{{25}}{{29}} \end{array}\) D \(\begin{array}{l} a)\,\,\,\frac{{17}}{{15}} & & & b)\,\,\frac{8}{5}\\ c)\,\,\frac{1}{6} & & & d)\,\,\frac{7}{{24}}\\ e)\,\,\frac{{15}}{{29}} \end{array}\)

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Tính: \(\begin{array}{l}a)\,\,\sqrt {\frac{{289}}{{225}}} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,b)\,\,\sqrt {2\frac{{14}}{{25}}} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,c)\,\,\sqrt {\frac{{0,25}}{9}} \\d)\,\,\sqrt {1\frac{{16}}{9}.5\frac{4}{9}.0,01} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,e)\,\,\sqrt {\frac{{{{149}^2} – {{76}^2}}}{{{{457}^2} – {{384}^2}}}} \end{array}\) A \(\begin{array}{l} a)\,\,\,\frac{{27}}{{15}} & & & b)\,\,\frac{8}{5}\\ c)\,\,\frac{1}{6} & …

Hỏi Đáp

Tính giá trị của tổng \(B = \sqrt {1 + \frac{1}{{{1^2}}} + \frac{1}{{{2^2}}}} + \sqrt {1 + \frac{1}{{{2^2}}} + \frac{1}{{{3^2}}}} + \sqrt {1 + \frac{1}{{{3^2}}} + \frac{1}{{{4^2}}}} + … + \sqrt {1 + \frac{1}{{{{99}^2}}} + \frac{1}{{{{100}^2}}}} \) A \(B = 100\) B \(B = 12\) C \(B = 0\) D \(B = 99,99\)

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Tính giá trị của tổng \(B = \sqrt {1 + \frac{1}{{{1^2}}} + \frac{1}{{{2^2}}}} + \sqrt {1 + \frac{1}{{{2^2}}} + \frac{1}{{{3^2}}}} + \sqrt {1 + \frac{1}{{{3^2}}} …