Tháng Tư 4, 2026

Cho biểu thức: \(P = \frac{{2\sqrt x }}{{x – 1}} – \frac{1}{{1 – \sqrt x }} + \frac{{\sqrt x }}{{\sqrt x + 1}}\) với \(x \ge 0;x \ne 1\). a) Rút gọn \(P.\) b) Tìm \(x\) để \(P = 3\). A \(\begin{array}{l}{\rm{a)}}\,\,P = \frac{{\sqrt x – 1}}{{\sqrt x + 1}}\\{\rm{b)}}\,\,x = 1\end{array}\) B \(\begin{array}{l}{\rm{a)}}\,\,P = \frac{1}{{\sqrt x – 1}}\\{\rm{b)}}\,\,x = 2\end{array}\) C \(\begin{array}{l}{\rm{a)}}\,\,P = \frac{1}{{\sqrt x + 1}}\\{\rm{b)}}\,\,x = 3\end{array}\) D \(\begin{array}{l}{\rm{a)}}\,\,P = \frac{{\sqrt x + 1}}{{\sqrt x – 1}}\\{\rm{b)}}\,\,x = 4\end{array}\)

Cho biểu thức: \(P = \frac{{2\sqrt x }}{{x – 1}} – \frac{1}{{1 – \sqrt x }} + \frac{{\sqrt x }}{{\sqrt x + 1}}\) với \(x …

Rút gọn: \(\begin{array}{l}a)\,\,\,A = \left( {x – y} \right)\sqrt {\frac{3}{{y – x}}} \\b)\,\,B = 2\sqrt {3x} – \sqrt {48x} + \sqrt {108x} + \sqrt {3x} \,\,\,\,\,\left( {x \ge 0} \right)\\c)\,\,\,C = \frac{1}{{1 – 5x}}\sqrt {3{x^2}\left( {25{x^2} – 10x + 1} \right)} ,\,\,\,0 \le x \le \frac{1}{5}\\d)\,\,D = 2\sqrt {25xy} + \sqrt {225{x^3}{y^3}} – 3y\sqrt {16{x^3}y} \,\,\,\,\left( {x \ge 0,\,\,y \ge 0} \right).\end{array}\) A \(\begin{array}{l} a)\,\,A = – \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 5\sqrt {3x} \\ c)\,\,C = x\sqrt 3 \\ d)\,\,\,D = \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\) B \(\begin{array}{l} a)\,\,A = \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 12\sqrt {3x} \\ c)\,\,C = x\sqrt 3 \\ d)\,\,\,D = \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\) C \(\begin{array}{l} a)\,\,A = – \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 12\sqrt {3x} \\ c)\,\,C = x\sqrt 3 \\ d)\,\,\,D = – \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\) D \(\begin{array}{l} a)\,\,A = – \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 5\sqrt {3x} \\ c)\,\,C = -x\sqrt 3 \\ d)\,\,\,D = \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\)

Rút gọn: \(\begin{array}{l}a)\,\,\,A = \left( {x – y} \right)\sqrt {\frac{3}{{y – x}}} \\b)\,\,B = 2\sqrt {3x} – \sqrt {48x} + \sqrt {108x} + \sqrt {3x} …