Cho \(A = \frac{{x + 2}}{{x\sqrt x – 1}} + \frac{{\sqrt x + 1}}{{x + \sqrt x + 1}} + \frac{1}{{1 – \sqrt x }}\) với \(x \ge 0,x \ne 1.\) a) Rút gọn
Cho \(A = \frac{{x + 2}}{{x\sqrt x – 1}} + \frac{{\sqrt x + 1}}{{x + \sqrt x + 1}} + \frac{1}{{1 – \sqrt x }}\) …