Cho biểu thức \(T = \frac{{15\sqrt x – 11}}{{x + 2\sqrt x – 3}} – \frac{{3\sqrt x – 2}}{{\sqrt x – 1}} – \frac{{2\sqrt x + 3}}{{\sqrt x + 3}}\) với điều kiện \(x \ge 0,x \ne 1\) a) Rút gọn T b) Tìm x để \(T = \frac{1}{2}\). A \(\begin{array}{l} a)\,\,T = \frac{{ – \left( {5\sqrt x – 2} \right)}}{{\sqrt x + 3}}\\ b)\,\,x = \frac{1}{{11}} \end{array}\) B \(\begin{array}{l} a)\,\,T = \frac{{ – \left( {5\sqrt x – 2} \right)}}{{\sqrt x + 3}}\\ b)\,\,x = \frac{1}{{121}} \end{array}\) C \(\begin{array}{l} a)\,\,T = \frac{{ {5\sqrt x – 2} }}{{\sqrt x + 3}}\\ b)\,\,x = \frac{1}{{121}} \end{array}\) D \(\begin{array}{l} a)\,\,T = \frac{{ {5\sqrt x – 2} }}{{\sqrt x + 3}}\\ b)\,\,x = \frac{1}{{11}} \end{array}\)
Cho biểu thức \(T = \frac{{15\sqrt x – 11}}{{x + 2\sqrt x – 3}} – \frac{{3\sqrt x – 2}}{{\sqrt x – 1}} – \frac{{2\sqrt x …