\(3\sqrt {80} – 2\sqrt {45} – \sqrt {125} \) A \(\sqrt 5 \) B \(2\sqrt 5 \) C \(3\sqrt 5 \) D \( – \sqrt 5 \)
by \(3\sqrt {80} – 2\sqrt {45} – \sqrt {125} \) A \(\sqrt 5 \) B \(2\sqrt 5 \) C \(3\sqrt 5 \) D \( – \sqrt …
Thẻ: Toán lớp 9
\(4\sqrt {12} – 15\sqrt {\frac{1}{3}} – \frac{{9 – \sqrt 3 }}{{\sqrt 3 }}\) A \(1\) B \(2\) C \(3\) D \(4\)
\(4\sqrt {12} – 15\sqrt {\frac{1}{3}} – \frac{{9 – \sqrt 3 }}{{\sqrt 3 }}\) A \(1\) B \(2\) C \(3\) D \(4\) Hướng dẫn Chọn đáp …
\(2\sqrt {48} + \frac{1}{3}\sqrt {108} – 5\sqrt 3 – 3\sqrt {27} \). A \( – 4\sqrt 3 \) B \(4\sqrt 3 \) C \(5\sqrt 3 \) D \( – 5\sqrt 3 \)
\(2\sqrt {48} + \frac{1}{3}\sqrt {108} – 5\sqrt 3 – 3\sqrt {27} \). A \( – 4\sqrt 3 \) B \(4\sqrt 3 \) C \(5\sqrt 3 …
\(\frac{{6 – \sqrt 6 }}{{\sqrt 6 – 1}} – 9\sqrt {\frac{2}{3}} – \frac{4}{{2 – \sqrt 6 }}\). A \(4\sqrt 6 \) B \(4\) C \(5\) D \(5\sqrt 6 \)
\(\frac{{6 – \sqrt 6 }}{{\sqrt 6 – 1}} – 9\sqrt {\frac{2}{3}} – \frac{4}{{2 – \sqrt 6 }}\). A \(4\sqrt 6 \) B \(4\) C \(5\) …
a) Tính chu vi tam giác ABC biết độ dài 3 cạnh là \(AB = 5\sqrt 2 \left( {cm} \right),AC = \sqrt {32} \left( {cm} \right)\), \(BC = \sqrt {98} \left( {cm} \right)\). (Không yêu cầu vẽ hình) b) Thu gọn: \(B = \sqrt {{{\left( {\sqrt 7 – 1} \right)}^2}} – \frac{6}{{\sqrt 7 – 1}}\). A \(\begin{array}{l}a)\,\,16\sqrt 2 \,\,cm\\b)\,\,B = – 2\end{array}\) B \(\begin{array}{l}a)\,\,16\,\,cm\\b)\,\,B = \sqrt 7 + 1\end{array}\) C \(\begin{array}{l}a)\,\,18\sqrt 2 \,\,cm\\b)\,\,B = \sqrt 7 – 1\end{array}\) D \(\begin{array}{l}a)\,\,18\,\,cm\\b)\,\,B = \frac{1}{{\sqrt 7 – 1}}\end{array}\)
a) Tính chu vi tam giác ABC biết độ dài 3 cạnh là \(AB = 5\sqrt 2 \left( {cm} \right),AC = \sqrt {32} \left( {cm} …
Thực hiện phép tính: 1)\(A = \sqrt {12} – 2\sqrt {48} + \frac{7}{5}\sqrt {75} \) 2)\(B = \sqrt {14 – 6\sqrt 5 } + \sqrt {{{\left( {2 – \sqrt 5 } \right)}^2}} \) A \(\begin{array}{l}1)\,\,\sqrt 3 \\2)\,\,2\sqrt 5 + 1\end{array}\) B \(\begin{array}{l}1)\,\,\sqrt 2 \\2)\,\,2\sqrt 5 \end{array}\) C \(\begin{array}{l}1)\,\,\sqrt 3 \\2)\,\,2\sqrt 5 – 1\end{array}\) D \(\begin{array}{l}1)\,\,\sqrt 2 \\2)\,\,2\sqrt 5 – 1\end{array}\)
Thực hiện phép tính: 1)\(A = \sqrt {12} – 2\sqrt {48} + \frac{7}{5}\sqrt {75} \) 2)\(B = \sqrt {14 – 6\sqrt 5 } + \sqrt …
Hãy tính giá trị của: a) \(M = \left( {2\sqrt {300} + 3\sqrt {48} – 4\sqrt {75} } \right):\sqrt 3 \) ; b) \(N = \sqrt {{{\left( {\sqrt 3 – 2} \right)}^2}} + \sqrt {4 – 2\sqrt 3 } \) ; c) \(P = \frac{2}{{\sqrt 3 + 1}} – \frac{1}{{\sqrt 3 – 2}} + \frac{{12}}{{\sqrt 3 + 3}}\). A \(\begin{array}{l}a)\,\,M = 12\\b)\,\,N = 1\\c)\,\,P = 7\end{array}\) B \(\begin{array}{l}a)\,\,M = 12\sqrt 3 \\b)\,\,N = 2\sqrt 3 \\c)\,\,P = 7\end{array}\) C \(\begin{array}{l}a)\,\,M = 12\\b)\,\,N = 2\sqrt 3 \\c)\,\,P = 7\sqrt 3 \end{array}\) D \(\begin{array}{l}a)\,\,M = 10\\b)\,\,N = 2\\c)\,\,P = 7\end{array}\)
Hãy tính giá trị của: a) \(M = \left( {2\sqrt {300} + 3\sqrt {48} – 4\sqrt {75} } \right):\sqrt 3 \) ; b) \(N = …
Thực hiện phép tính a) \(2\sqrt {50} – 3\sqrt {32} – \sqrt {162} + 5\sqrt {98} \) b) \(\sqrt {8 + 2\sqrt 7 } + \sqrt {11 – 4\sqrt 7 } \) c) \(\frac{{10}}{{\sqrt 5 }} + \frac{8}{{3 + \sqrt 5 }} – \frac{{\sqrt {18} – 3\sqrt 5 }}{{\sqrt 2 – \sqrt 5 }}\) A \(\begin{array}{l}a)\,\,24\sqrt 2 \\b)\,\,2\sqrt 7 – 1\\c)\,\,3\end{array}\) B \(\begin{array}{l}a)\,\,24\sqrt 2 \\b)\,\,2\sqrt 7 + 1\\c)\,\,4\sqrt 5 + 3\end{array}\) C \(\begin{array}{l}a)\,\,22\sqrt 2 \\b)\,\,2\sqrt 7 + 1\\c)\,\,3\end{array}\) D \(\begin{array}{l}a)\,\,22\sqrt 2 \\b)\,\,2\sqrt 7 – 1\\c)\,\,4\sqrt 5 + 3\end{array}\)
Thực hiện phép tính a) \(2\sqrt {50} – 3\sqrt {32} – \sqrt {162} + 5\sqrt {98} \) b) \(\sqrt {8 + 2\sqrt 7 } + …
Thực hiện phép tính: a) \(3\sqrt {\frac{1}{3}} + 4\sqrt {12} – 5\sqrt {27} \) b) \(\frac{{3 + 2\sqrt 3 }}{{\sqrt 3 }} – \frac{2}{{\sqrt 3 – 1}}\) A \(\begin{array}{l}a)\,\, – 6\sqrt 3 \\b)\,\,1\end{array}\) B \(\begin{array}{l}a)\,\, – 6\sqrt 3 \\b)\,\,2\sqrt 3 \end{array}\) C \(\begin{array}{l}a)\,\,6\sqrt 3 \\b)\,\,1\end{array}\) D \(\begin{array}{l}a)\,\,6\sqrt 3 \\b)\,\,2\sqrt 3 \end{array}\)
Thực hiện phép tính: a) \(3\sqrt {\frac{1}{3}} + 4\sqrt {12} – 5\sqrt {27} \) b) \(\frac{{3 + 2\sqrt 3 }}{{\sqrt 3 }} – \frac{2}{{\sqrt 3 …
Tính: \(A=\frac{\sqrt{2}}{2\sqrt{2}+\sqrt{3+\sqrt{5}}}+\frac{\sqrt{2}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\) A 1 B 3 C 2 D 4
Tính: \(A=\frac{\sqrt{2}}{2\sqrt{2}+\sqrt{3+\sqrt{5}}}+\frac{\sqrt{2}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\) A 1 B 3 C 2 D 4 Hướng dẫn Chọn đáp án là: A Lời giải chi tiết: Ta có \(\begin{array}{l}A = …