Tháng Năm 8, 2026

Danh mục: Hỏi Đáp

Hỏi Đáp

Thực hiện phép tính : \(a)\,\,\sqrt {20} – 3\sqrt {125} + 5\sqrt {45} \) \(b)\,\,\frac{3}{{\sqrt 3 – \sqrt 2 }} – 2\sqrt {{{\left( {\sqrt 2 – \sqrt 3 } \right)}^2}} – 5\sqrt 2 \) A \(\begin{array}{l}a)\,\,\sqrt 5 \\b)\,\,\sqrt 3 \end{array}\) B \(\begin{array}{l}a)\,\,2\sqrt 5 \\b)\,\,\sqrt 3 \end{array}\) C \(\begin{array}{l}a)\,\,\sqrt 5 \\b)\,\,2\sqrt 3 \end{array}\) D \(\begin{array}{l}a)\,\,2\sqrt 5 \\b)\,\,2\sqrt 3 \end{array}\)

adminby admin

Thực hiện phép tính : \(a)\,\,\sqrt {20} – 3\sqrt {125} + 5\sqrt {45} \) \(b)\,\,\frac{3}{{\sqrt 3 – \sqrt 2 }} – 2\sqrt {{{\left( {\sqrt 2 …

Hỏi Đáp

Giải các phương trình sau : a) \(\sqrt {x – 1} + \sqrt {9x – 9} + \sqrt {4x – 4} = 12;\) b) \(\sqrt {{x^2} – 5x} – \sqrt {x – 5} = 0\) A \(\begin{array}{l}{\rm{a)}}\,\,x = 1\\{\rm{b)}}\,\,x = 5\end{array}\) B \(\begin{array}{l}{\rm{a)}}\,\,x = 2\\{\rm{b)}}\,\,x = 6\end{array}\) C \(\begin{array}{l}{\rm{a)}}\,\,x = 2\\{\rm{b)}}\,\,x = 6\end{array}\) D \(\begin{array}{l}{\rm{a)}}\,\,x = 5\\{\rm{b)}}\,\,x = 5\end{array}\)

adminby admin

Giải các phương trình sau : a) \(\sqrt {x – 1} + \sqrt {9x – 9} + \sqrt {4x – 4} = 12;\) b) \(\sqrt …

Hỏi Đáp

Giải các phương trình sau: a) \(\sqrt {{x^2} – 6x + 9} = 1\) b) \(2\sqrt {12x} – 3\sqrt {3x} + 4\sqrt {48x} = 17.\) A \(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ { – 2;4} \right\}.\\{\rm{b)}}\,\,S = \left\{ {\frac{1}{2}} \right\}.\end{array}\) B \(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ {2; – 4} \right\}.\\{\rm{b)}}\,\,S = \left\{ 3 \right\}.\end{array}\) C \(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ {2;4} \right\}.\\{\rm{b)}}\,\,S = \left\{ {\frac{1}{3}} \right\}.\end{array}\) D \(\begin{array}{l}{\rm{a)}}\,\,S = \left\{ { – 2; – 4} \right\}.\\{\rm{b)}}\,\,S = \left\{ 2 \right\}.\end{array}\)

adminby admin

Giải các phương trình sau: a) \(\sqrt {{x^2} – 6x + 9} = 1\) b) \(2\sqrt {12x} – 3\sqrt {3x} + 4\sqrt {48x} = 17.\) …

Hỏi Đáp

Tính : a) \(\frac{5}{{\sqrt 5 – 1}} – \frac{5}{{\sqrt 5 + 1}};\) b) \(\sqrt {{{\left( {\sqrt 5 – 3} \right)}^2}} – \sqrt {\frac{1}{5}} \) A \(\begin{array}{l}{\rm{a)}}\,\,\frac{1}{2}\\{\rm{b)}}\,\,\frac{{15 + 3\sqrt 5 }}{5}\end{array}\) B \(\begin{array}{l}{\rm{a)}}\,\,\frac{3}{2}\\{\rm{b)}}\,\,\frac{{15 – 3\sqrt 5 }}{5}\end{array}\) C \(\begin{array}{l}{\rm{a)}}\,\,\frac{5}{2}\\{\rm{b)}}\,\,\frac{{15 – 6\sqrt 5 }}{5}\end{array}\) D \(\begin{array}{l}{\rm{a)}}\,\,2\\{\rm{b)}}\,\,\frac{{15 + 6\sqrt 5 }}{5}\end{array}\)

adminby admin

Tính : a) \(\frac{5}{{\sqrt 5 – 1}} – \frac{5}{{\sqrt 5 + 1}};\) b) \(\sqrt {{{\left( {\sqrt 5 – 3} \right)}^2}} – \sqrt {\frac{1}{5}} \) A …