Tháng Tư 25, 2026

Tìm \(x\) biết: \(a)\,\,\frac{{\sqrt {2x – 1} }}{{\sqrt {x – 1} }} = 2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,b)\,\,\frac{{\sqrt {{x^2} – 4} }}{{\sqrt {x – 2} }} = 3\) A \(\begin{array}{l} a)\,\,\,S = \left\{ {\frac{3}{2}} \right\}.\\ b)\,\,S = \left\{- 7 \right\}. \end{array}\) B \(\begin{array}{l} a)\,\,\,S = \left\{ {\frac{3}{2}} \right\}.\\ b)\,\,S = \left\{ 7 \right\}. \end{array}\) C \(\begin{array}{l} a)\,\,\,S = \left\{ {\frac{3}{2}} \right\}.\\ b)\,\,S = \left\{ 2 \right\}. \end{array}\) D \(\begin{array}{l} a)\,\,\,S = \left\{ {\frac{3}{2}} \right\}.\\ b)\,\,S = \left\{ 2;\,7 \right\}. \end{array}\)

Tìm \(x\) biết: \(a)\,\,\frac{{\sqrt {2x – 1} }}{{\sqrt {x – 1} }} = 2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,b)\,\,\frac{{\sqrt {{x^2} – 4} }}{{\sqrt {x – 2} }} = 3\) A …