Tháng Năm 23, 2026

Tác giả: admin

Hỏi Đáp

Rút gọn: \(\begin{array}{l}a)\,\,\,A = \left( {x – y} \right)\sqrt {\frac{3}{{y – x}}} \\b)\,\,B = 2\sqrt {3x} – \sqrt {48x} + \sqrt {108x} + \sqrt {3x} \,\,\,\,\,\left( {x \ge 0} \right)\\c)\,\,\,C = \frac{1}{{1 – 5x}}\sqrt {3{x^2}\left( {25{x^2} – 10x + 1} \right)} ,\,\,\,0 \le x \le \frac{1}{5}\\d)\,\,D = 2\sqrt {25xy} + \sqrt {225{x^3}{y^3}} – 3y\sqrt {16{x^3}y} \,\,\,\,\left( {x \ge 0,\,\,y \ge 0} \right).\end{array}\) A \(\begin{array}{l} a)\,\,A = – \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 5\sqrt {3x} \\ c)\,\,C = x\sqrt 3 \\ d)\,\,\,D = \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\) B \(\begin{array}{l} a)\,\,A = \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 12\sqrt {3x} \\ c)\,\,C = x\sqrt 3 \\ d)\,\,\,D = \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\) C \(\begin{array}{l} a)\,\,A = – \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 12\sqrt {3x} \\ c)\,\,C = x\sqrt 3 \\ d)\,\,\,D = – \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\) D \(\begin{array}{l} a)\,\,A = – \sqrt {3\left( {y – x} \right)} \\ b)\,\,\,B = 5\sqrt {3x} \\ c)\,\,C = -x\sqrt 3 \\ d)\,\,\,D = \sqrt {xy} \left( {10 + 3xy} \right) \end{array}\)

adminby admin

Rút gọn: \(\begin{array}{l}a)\,\,\,A = \left( {x – y} \right)\sqrt {\frac{3}{{y – x}}} \\b)\,\,B = 2\sqrt {3x} – \sqrt {48x} + \sqrt {108x} + \sqrt {3x} …