Tháng Năm 8, 2026

Hãy tính giá trị của: a) \(M = \left( {2\sqrt {300} + 3\sqrt {48} – 4\sqrt {75} } \right):\sqrt 3 \) ; b) \(N = \sqrt {{{\left( {\sqrt 3 – 2} \right)}^2}} + \sqrt {4 – 2\sqrt 3 } \) ; c) \(P = \frac{2}{{\sqrt 3 + 1}} – \frac{1}{{\sqrt 3 – 2}} + \frac{{12}}{{\sqrt 3 + 3}}\). A \(\begin{array}{l}a)\,\,M = 12\\b)\,\,N = 1\\c)\,\,P = 7\end{array}\) B \(\begin{array}{l}a)\,\,M = 12\sqrt 3 \\b)\,\,N = 2\sqrt 3 \\c)\,\,P = 7\end{array}\) C \(\begin{array}{l}a)\,\,M = 12\\b)\,\,N = 2\sqrt 3 \\c)\,\,P = 7\sqrt 3 \end{array}\) D \(\begin{array}{l}a)\,\,M = 10\\b)\,\,N = 2\\c)\,\,P = 7\end{array}\)

Hãy tính giá trị của: a) \(M = \left( {2\sqrt {300} + 3\sqrt {48} – 4\sqrt {75} } \right):\sqrt 3 \) ; b) \(N = …

Thực hiện phép tính a) \(2\sqrt {50} – 3\sqrt {32} – \sqrt {162} + 5\sqrt {98} \) b) \(\sqrt {8 + 2\sqrt 7 } + \sqrt {11 – 4\sqrt 7 } \) c) \(\frac{{10}}{{\sqrt 5 }} + \frac{8}{{3 + \sqrt 5 }} – \frac{{\sqrt {18} – 3\sqrt 5 }}{{\sqrt 2 – \sqrt 5 }}\) A \(\begin{array}{l}a)\,\,24\sqrt 2 \\b)\,\,2\sqrt 7 – 1\\c)\,\,3\end{array}\) B \(\begin{array}{l}a)\,\,24\sqrt 2 \\b)\,\,2\sqrt 7 + 1\\c)\,\,4\sqrt 5 + 3\end{array}\) C \(\begin{array}{l}a)\,\,22\sqrt 2 \\b)\,\,2\sqrt 7 + 1\\c)\,\,3\end{array}\) D \(\begin{array}{l}a)\,\,22\sqrt 2 \\b)\,\,2\sqrt 7 – 1\\c)\,\,4\sqrt 5 + 3\end{array}\)

Thực hiện phép tính a) \(2\sqrt {50} – 3\sqrt {32} – \sqrt {162} + 5\sqrt {98} \) b) \(\sqrt {8 + 2\sqrt 7 } + …

Thực hiện phép tính: a) \(3\sqrt {\frac{1}{3}} + 4\sqrt {12} – 5\sqrt {27} \) b) \(\frac{{3 + 2\sqrt 3 }}{{\sqrt 3 }} – \frac{2}{{\sqrt 3 – 1}}\) A \(\begin{array}{l}a)\,\, – 6\sqrt 3 \\b)\,\,1\end{array}\) B \(\begin{array}{l}a)\,\, – 6\sqrt 3 \\b)\,\,2\sqrt 3 \end{array}\) C \(\begin{array}{l}a)\,\,6\sqrt 3 \\b)\,\,1\end{array}\) D \(\begin{array}{l}a)\,\,6\sqrt 3 \\b)\,\,2\sqrt 3 \end{array}\)

Thực hiện phép tính: a) \(3\sqrt {\frac{1}{3}} + 4\sqrt {12} – 5\sqrt {27} \) b) \(\frac{{3 + 2\sqrt 3 }}{{\sqrt 3 }} – \frac{2}{{\sqrt 3 …

Phân tích các đa thức sau thành nhân tử: \( \eqalign{& a)\,\,2x – 7\sqrt x – 9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,d)\,\,3x + 2\sqrt x – 5 \cr & b)\,\,x – 9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \,\,\,e)\,\,\,4\sqrt x – x – 4 \cr & c)\,\,x\sqrt x – 1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,f)\,\,x + \sqrt x – 6 \cr} \)

Phân tích các đa thức sau thành nhân tử: \( \eqalign{& a)\,\,2x – 7\sqrt x – 9\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,d)\,\,3x + 2\sqrt x – 5 \cr & b)\,\,x …

Tính: a) \(\sqrt{18}-\frac{1}{2}\sqrt{48}-\sqrt{8}+\frac{4-5\sqrt{2}}{5-2\sqrt{2}}\) b) \(\sqrt{{{(2-\sqrt{7})}^{2}}}-\sqrt{\frac{2}{8-3\sqrt{7}}}\) c) \(\frac{\sqrt{8-4\sqrt{3}}}{\sqrt{\sqrt{6}-\sqrt{2}}}.\sqrt{\sqrt{6}+\sqrt{2}}\)

Tính: a) \(\sqrt{18}-\frac{1}{2}\sqrt{48}-\sqrt{8}+\frac{4-5\sqrt{2}}{5-2\sqrt{2}}\) b) \(\sqrt{{{(2-\sqrt{7})}^{2}}}-\sqrt{\frac{2}{8-3\sqrt{7}}}\) c) \(\frac{\sqrt{8-4\sqrt{3}}}{\sqrt{\sqrt{6}-\sqrt{2}}}.\sqrt{\sqrt{6}+\sqrt{2}}\) Phương pháp giải: Phương pháp: +) Câu a: Khai căn thức bậc hai dựa vào công thức: \(\sqrt{{{A}^{2}}.B}=\left| …

Thực hiện phép tính: 1)\(A = \sqrt {12} – 2\sqrt {48} + \frac{7}{5}\sqrt {75} \) 2)\(B = \sqrt {14 – 6\sqrt 5 } + \sqrt {{{\left( {2 – \sqrt 5 } \right)}^2}} \) A \(\begin{array}{l}1)\,\,\sqrt 3 \\2)\,\,2\sqrt 5 + 1\end{array}\) B \(\begin{array}{l}1)\,\,\sqrt 2 \\2)\,\,2\sqrt 5 \end{array}\) C \(\begin{array}{l}1)\,\,\sqrt 3 \\2)\,\,2\sqrt 5 – 1\end{array}\) D \(\begin{array}{l}1)\,\,\sqrt 2 \\2)\,\,2\sqrt 5 – 1\end{array}\)

Thực hiện phép tính: 1)\(A = \sqrt {12} – 2\sqrt {48} + \frac{7}{5}\sqrt {75} \) 2)\(B = \sqrt {14 – 6\sqrt 5 } + \sqrt …

Tính giá trị của các biểu thức: \(a)\;A = 5\sqrt {27} – 5\sqrt 3 – 2\sqrt {12} \) \(b)\;B = \frac{{\sqrt {15} – \sqrt 3 }}{{\sqrt 5 – 1}} – \frac{{\sqrt {15} + \sqrt 3 }}{{\sqrt 5 + 1}}\) A \(\begin{array}{l}a)\,\,A = 6\sqrt 3 \\b)\,\,B = 0\end{array}\) B \(\begin{array}{l}a)\,\,A = 6\sqrt 3 \\b)\,\,B = \sqrt 3 \end{array}\) C \(\begin{array}{l}a)\,\,A = 3\sqrt 3 \\b)\,\,B = 0\end{array}\) D \(\begin{array}{l}a)\,\,A = 3\sqrt 3 \\b)\,\,B = \sqrt 3 \end{array}\)

Tính giá trị của các biểu thức: \(a)\;A = 5\sqrt {27} – 5\sqrt 3 – 2\sqrt {12} \) \(b)\;B = \frac{{\sqrt {15} – \sqrt 3 …