Tháng Năm 7, 2026

Cho tam giác \(ABC\) vuông tại \(A\) có \(AB{\rm{ }} = {\rm{ }}6cm,\angle B = \alpha \), biết \({\rm{tan}}\alpha = \frac{5}{{12}}.\) Hãy tính: \(BC;AC\) A \(BC = 6,5cm\,\,;\,\,\,AC = 2,5cm\) B \(BC = 7cm\,\,;\,\,\,AC = 3cm\) C \(BC = 7cm\,\,;\,\,\,AC = 3,5cm\) D \(BC = 7,5cm\,\,;\,\,\,AC = 3,5cm\)

Cho tam giác \(ABC\) vuông tại \(A\) có \(AB{\rm{ }} = {\rm{ }}6cm,\angle B = \alpha \), biết \({\rm{tan}}\alpha = \frac{5}{{12}}.\) Hãy tính: \(BC;AC\) A …

\(AC{\rm{ }} = {\rm{ 12}}cm;CB = 13cm\) A \(AB = 5cm\,\,;\,\,\angle B = {22^0}37’\,\,;\,\,\angle C = {67^0}23’\) B \(AB = 5cm\,\,;\,\,\angle B = {67^0}23’\,\,;\,\,\angle C = {22^0}37’\) C \(AB = 5cm\,\,;\,\,\angle B = {24^0}37’\,\,;\,\,\angle C = {65^0}23’\) D \(AB = 5cm\,\,;\,\,\angle B = {65^0}23’\,\,;\,\,\angle C = {24^0}37’\)

\(AC{\rm{ }} = {\rm{ 12}}cm;CB = 13cm\) A \(AB = 5cm\,\,;\,\,\angle B = {22^0}37’\,\,;\,\,\angle C = {67^0}23’\) B \(AB = 5cm\,\,;\,\,\angle B = {67^0}23’\,\,;\,\,\angle C …

\(AB{\rm{ }} = {\rm{ 18}}cm;AC = 21cm\) A \(BC = 3\sqrt {85} \,\,;\,\,\angle B = {59^0}\,\,;\,\,\angle C = {31^0}\) B \(BC = 3\sqrt {85} \,\,;\,\,\angle B = {31^0}\,\,;\,\,\angle C = {59^0}\) C \(BC = 3\sqrt {85} \,\,;\,\,\angle B = {40^0}36’\,\,;\,\,\angle C = {49^0}24’\) D \(BC = 3\sqrt {85} \,\,;\,\,\angle B = {49^0}24’\,\,;\,\,\angle C = {40^0}36’\)

\(AB{\rm{ }} = {\rm{ 18}}cm;AC = 21cm\) A \(BC = 3\sqrt {85} \,\,;\,\,\angle B = {59^0}\,\,;\,\,\angle C = {31^0}\) B \(BC = 3\sqrt {85} \,\,;\,\,\angle …

\(\angle C = {30^0}\) và \(BC{\rm{ }} = {\rm{ 16}}\) A \(AB = 8\,\,;\,\,AC = 8\sqrt 3 \,\,;\,\,\angle B = {60^0}\) B \(AB = 8\sqrt 3 \,\,;\,\,AC = 8\,\,;\,\,\angle B = {60^0}\) C \(AB = \frac{{16\sqrt 3 }}{3}\,\,;\,\,AC = \frac{{16\sqrt 6 }}{3}\,\,;\,\,\angle B = {60^0}\) D \(AB = \frac{{16\sqrt 6 }}{3}\,\,;\,\,AC = \frac{{16\sqrt 3 \,}}{3}\,;\,\,\angle B = {60^0}\)

\(\angle C = {30^0}\) và \(BC{\rm{ }} = {\rm{ 16}}\) A \(AB = 8\,\,;\,\,AC = 8\sqrt 3 \,\,;\,\,\angle B = {60^0}\) B \(AB = 8\sqrt …