Cho sơ đồ chuyển hóa sau: $Cr\xrightarrow{+HCl\text{ }\left( l \right)}\left( X \right)\xrightarrow{+C{{l}_{2}},t{}^\circ }\left( M \right)$ $\xrightarrow{+B{{r}_{2}}+KOH}\left( Z \right)\xrightarrow{+{{H}_{2}}S{{O}_{4}}\left( l \right)}\left( T \right)\xrightarrow{FeS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}}\left( Y \right)$ T và Y lần lượt là?

Cho sơ đồ chuyển hóa sau:

$Cr\xrightarrow{+HCl\text{ }\left( l \right)}\left( X \right)\xrightarrow{+C{{l}_{2}},t{}^\circ }\left( M \right)$ $\xrightarrow{+B{{r}_{2}}+KOH}\left( Z \right)\xrightarrow{+{{H}_{2}}S{{O}_{4}}\left( l \right)}\left( T \right)\xrightarrow{FeS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}}\left( Y \right)$

T và Y lần lượt là?

A. ${{K}_{2}}Cr{{O}_{4}}$ và $C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}$.

B. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ và $CrC{{l}_{3}}$.

C. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ và $CrS{{O}_{4}}$.

D. ${{K}_{2}}C{{r}_{2}}{{O}_{7}}$ và $C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}$.

Hướng dẫn

Đáp án D

$Cr\xrightarrow[{}]{+HCl\left( l \right)}CrC{{l}_{2}}\xrightarrow[{}]{+C{{l}_{2}}}CrC{{l}_{3}}\xrightarrow[{}]{+B{{r}_{2}}+KOH}{{K}_{2}}Cr{{O}_{4}}$

$\xrightarrow[{}]{{{H}_{2}}S{{O}_{4}}\text{ loa }\!\!\tilde{\mathrm{o}}\!\!\text{ ng}}{{K}_{2}}C{{r}_{2}}{{O}_{7}}\xrightarrow[{}]{FeS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}}C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}$

Có các phương trình:

1) $Cr+2HC{{l}_{\left( l \right)}}\xrightarrow[{}]{{}}CrC{{l}_{2}}\left( X \right)+{{H}_{2}}$

2) $2CrC{{l}_{2}}+C{{l}_{2}}\xrightarrow[{}]{t{}^\circ }2CrC{{l}_{3}}\left( Y \right)$

3) $2CrC{{l}_{3}}+3B{{r}_{2}}+16KOH\xrightarrow[{}]{{}}2{{K}_{2}}Cr{{O}_{4}}\left( Z \right)+6KBr+6KCl+8{{H}_{2}}O$

4) $2{{K}_{2}}Cr{{O}_{4}}+{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}{{K}_{2}}C{{r}_{2}}{{O}_{7}}\left( T \right)+{{K}_{2}}S{{O}_{4}}+{{H}_{2}}O$

5) $6FeS{{O}_{4}}+{{K}_{2}}C{{r}_{2}}{{O}_{7}}+7{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}3F{{e}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}+C{{r}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\left( M \right)+{{K}_{2}}S{{O}_{4}}+7{{H}_{2}}O$