Tháng Tư 2, 2026

$a=45/(\frac{1}{\sqrt{{{10}^{3. 8}}}}-\frac{1}{\sqrt{{{10}^{4. 5}}}});BC=a(\frac{1}{\sqrt{{{10}^{2. 6}}}}-\frac{1}{\sqrt{{{10}^{3. 8}}}})\approx 242. 5(m)$ ##categories: 11493## ##tags: Vật lý 12##

$a=45/(\frac{1}{\sqrt{{{10}^{3. 8}}}}-\frac{1}{\sqrt{{{10}^{4. 5}}}});BC=a(\frac{1}{\sqrt{{{10}^{2. 6}}}}-\frac{1}{\sqrt{{{10}^{3. 8}}}})\approx 242. 5(m)$